Liczby całkowite, wymierne i niewymierne - wyrażenia algebraiczne
Wzory
Wzór
Przykład
a
+
b
2
=
a
2
+
2
a
b
+
b
2
x
+
5
2
=
x
2
+
2
⋅
x
⋅
5
+
5
2
=
x
2
+
10
x
+
25
a
-
b
2
=
a
2
-
2
a
b
+
b
2
2
x
-
1
2
=
2
x
2
-
2
⋅
2
x
⋅
1
+
1
2
=
4
x
2
-
4
x
+
1
a
2
-
b
2
=
a
+
b
a
-
b
4
x
2
-
9
=
2
x
2
-
3
2
=
2
x
+
3
2
x
-
3
a
+
b
3
=
a
3
+
3
a
2
b
+
3
a
b
2
+
b
3
2
x
+
3
3
=
2
x
3
+
3
⋅
2
x
2
⋅
3
+
3
⋅
2
x
⋅
3
2
+
3
3
=
8
x
3
+
36
x
2
+
54
x
+
27
a
-
b
3
=
a
3
-
3
a
2
b
+
3
a
b
2
-
b
3
2
-
3
x
3
=
2
3
-
3
⋅
2
2
⋅
3
x
+
3
⋅
2
⋅
3
x
2
-
3
⋅
x
3
=
8
-
36
x
+
54
x
2
-
27
x
3
a
n
a
m
=
a
n
+
m
2
3
2
5
=
2
8
a
n
a
m
=
a
n
-
m
10
7
10
2
=
10
5
1
a
n
=
a
-
n
1
3
3
=
3
-
3
a
⋅
b
=
a
b
3
⋅
5
=
15
a
2
=
|
a
|
3
2
=
3
,
-
3
2
=
3
Zadania
Ogólny opis zadań
Zadania